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I want to make space filling model for nitrogen molecule.

I've learned that van der Waals diameter is to be taken for atom radius.

Since van der Waals radius for nitrogen is $\pu{155 pm}$ and bond length is $\pu{110 pm}$, does this mean that nitrogen molecule space filling model is two blue spheres of diameter $\pu{155 pm}$ and center to center distance $\pu{110 pm}$?

One of the reasons for this question is that samples of space filling model for this molecule (see for example Wikipedia) do not agree with these data; there's about a 11% difference between the length/width ratio of the drawn molecule, and what it should be based on the van der Waals radius and bond length.


\begin{array}{cccccc} \displaystyle\frac{d}{2r} &\sim& \displaystyle\frac{\pu{1000 pix}-\pu{716pix}}{\pu{716 pix}} &\sim& 0.397\\ \displaystyle\frac{d}{2r} &\sim& \displaystyle\frac{\pu{110 pm}}{2\times\pu{155 pm}} &\sim& 0.355 \end{array}

enter image description here

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Yes, two spheres with a radius of 155 pm and the distance between the center is 110 pm.

The axis in that picture is not aligned, that's why you get an error. Here's a picture with aligned axis and van der vaals spheres produced in Avogadro:

enter image description here

The corresponding *.xyz:

2

N   -0.55   0.0 0.0
N   0.55    0.0 0.0

I'm also unable to follow your math here. height of the molecule should be $2\times 155=310$ and length should be $155\times 2+110=420$ so height to length ratio should be $0.73$, you got $0.72$ which is pretty close.

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  • $\begingroup$ I've edited your answer to make it match the question and removed the reference to my (now) deleted comment. (I also change \cdot to \times, because sometimes that looks like a decimal delimiter on some devices.) [Flag this comment obsolete when read ;)] $\endgroup$ – Martin - マーチン Jul 24 '17 at 10:53
  • $\begingroup$ Thanks. Could you please compare d/2r to make direct connection to the question? $\endgroup$ – Pygmalion Jul 24 '17 at 12:18

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