What is the critical temperature for an ideal gas? It can't be found from Andrew's isotherm as it is for real gases and states critical temperature as $\frac{8a}{27 R \cdot b}$, but for ideal gases $a = b = 0$.
Asked
Viewed
868 times
1
$\begingroup$
$\endgroup$
-
5$\begingroup$ The point is that ideal gasses don't have a critical temperature; by being composed of infinitesimal, completely non-interacting point particles, they are not subject to intermolecular interactions and phase changes. That's what makes them ideal, i.e. simple. $\endgroup$ – Nicolau Saker Neto Jul 22 '17 at 6:06
-
$\begingroup$ Thus they cant be liquified? $\endgroup$ – user161158 Jul 22 '17 at 6:22
-
2$\begingroup$ Sure enough, they can't. $\endgroup$ – Ivan Neretin Jul 22 '17 at 6:28
