What is the critical temperature for an ideal gas? It can't be found from Andrew's isotherm as it is for real gases and states critical temperature as $\frac{8a}{27 R \cdot b}$, but for ideal gases $a = b = 0$.
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5$\begingroup$ The point is that ideal gasses don't have a critical temperature; by being composed of infinitesimal, completely non-interacting point particles, they are not subject to intermolecular interactions and phase changes. That's what makes them ideal, i.e. simple. $\endgroup$– Nicolau Saker NetoJul 22, 2017 at 6:06
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$\begingroup$ Thus they cant be liquified? $\endgroup$– user161158Jul 22, 2017 at 6:22
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2$\begingroup$ Sure enough, they can't. $\endgroup$– Ivan NeretinJul 22, 2017 at 6:28
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