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What is the critical temperature for an ideal gas? It can't be found from Andrew's isotherm as it is for real gases and states critical temperature as $\frac{8a}{27 R \cdot b}$, but for ideal gases $a = b = 0$.

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    $\begingroup$ The point is that ideal gasses don't have a critical temperature; by being composed of infinitesimal, completely non-interacting point particles, they are not subject to intermolecular interactions and phase changes. That's what makes them ideal, i.e. simple. $\endgroup$ Jul 22, 2017 at 6:06
  • $\begingroup$ Thus they cant be liquified? $\endgroup$
    – user161158
    Jul 22, 2017 at 6:22
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    $\begingroup$ Sure enough, they can't. $\endgroup$ Jul 22, 2017 at 6:28

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