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I saw a different mechanism for esterification of tertiary alcohol in a book.

They say that first the $\ce{OH}$ is protonated and it leaves to form the tertiary carbocation. Then the oxygen's lone pair from the carboxylic acid attacks to form the ester.

Is this mechanism actually correct?

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    $\begingroup$ It depends on the conditions used $\endgroup$
    – NotEvans.
    Jul 3, 2017 at 18:20

2 Answers 2

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Yes, the mechanism is correct and is different from the normal mechanism because here the more stable tertiary carbocation formation.

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Upon esterification of a tertiary alcohol an alkene is formed as the major product, not an ester.

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