I took a look into some tetrahedrane (C4H4) analogs, platonic hydrocarbon, basically very strained tetrahedral geometry at every carbon. I was wondering what will be the predicted delta H of formation for the tetra nitro analog tetranitrotetrahedrane? What will be the predicted detonation velocity too? Could there be modified analogs that are even more energetic?

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    $\begingroup$ I think this a great question and deserves attention. AFAIK there is no published structures where any type of tetrahedron $\ce{N4}$ unit would be present. Maybe you could briefly mention azidoazide azides to spice the things up a little. $\endgroup$ – andselisk Jul 1 '17 at 1:50
  • $\begingroup$ What's "inverted tetrahedral" geometry? They're tetrahedral all right, just very strained. $\endgroup$ – Ivan Neretin Jul 1 '17 at 5:50
  • $\begingroup$ Yes, you are right, its the wrong term for tetrahedrane I was thinking about another molecule when writing this (1.1.1-propellane), I corrected the question, thanks for that. $\endgroup$ – AS_1000 Jul 1 '17 at 12:51
  • $\begingroup$ I read a paper a while back that computed the delta H of formation of cubane and I believe octanitrocubane. I will see if I can find that as a reference. $\endgroup$ – Tyberius Jul 2 '17 at 2:47
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    $\begingroup$ Have you heard of hydrazine? It's the most relaxed compound with a $\ce{N-N}$ bond. Even for that, Wikipedia says: Hydrazine is highly toxic and dangerously unstable unless handled in solution. Considering that fact, $\ce{N-N}$ bond is too weak to form tetrahedrane molecules. $\endgroup$ – Pritt says Reinstate Monica Jul 2 '17 at 9:56

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