A student is provided with 500 mL of 600 ppm solutions of fructose. What volume of this solution in millilitres contains 0.15 fructose?

Does this mean that I just have to use 600 ppm as the concentration and the 0.15 as the weight? Like this:

\begin{align*} {600 \space ppm} &=\frac {0.15 g}{x}\cdot 10^{6} \\ x&=\frac {0.15 }{600}\cdot 10^{6} \\ x&=250 \space mL\\ & \end{align*}

And when can 500 mL be used?

  • 6
    $\begingroup$ 0.15 whats of fructose? grammes, mols? $\endgroup$ – matt_black Jan 5 '14 at 23:38
  • $\begingroup$ I think if you don't provide the units of 0.15 this question will be close because is unclear what you are asking... $\endgroup$ – G M Feb 7 '14 at 16:23

Assuming it's $0.15gm$ of fructose,$$ppm=\frac{Weight\;of\;solute_{(in\;gm)}}{Weight\;of\;solution_{(in\;gm)}}10^6$$ Since density of water is $1gm/ml$, $500ml$ of water would weigh $500gm$ $$\therefore600=\frac{W_b}{500}10^6$$ $$\therefore W_b=0.3gm$$

Thus, $500ml$ of water contains $0.3gm$ of fructose. You can find out what volume will contain $0.15gm$ of it.


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