Paraquat is 4,4'dipyridinium chloride. There are two common ways to synthesise it starting with pyridine.

In one reaction that can be done on a large scale in water or liquid ammonia, methyl-pyridinium chloride is reacted with a base and catalytic amounts of sodium cyanide in the solvent to give a dimeric intermediate that oxidises easily into paraquat.

What is the chemical mechanism of the dimerisation reaction?


2 Answers 2


While the mechanism is not 100% certain (or wasn't when I worked on it some time ago), the current best guess is that it is similar to the well known Benzoin condensation:

benzoin condensation

This is based on the following intermediate:

benzoin first step

Applied to the paraquat conditions this might go like this:

paraquat reaction mechanism

The neutral quinone-like intermediate crystallises out of solution and can be separated and then oxidised (it is very oxygen sensitive) to the desired paraquat product.

The details are partially guesswork, though, as it isn't the easiest reaction to investigate mechanistically.


I remember PET (photoinduced electron transfer) works by the Mariano group in which N-dimethylallyl pyridinium perchlorate underwent intramolecular radical cyclizations upon uv irradiation and in fact, I've seen N-methyl chinolinium salts undergo dimerization under these conditions.

Imagine that the N-methylpyridinium cation is irradiated at $\lambda$ = 300 nm. The resulting $S_1$ state oxidizes cyanide to a cyanogen radical.

The N-methylpyridinium cation is thereby reduced to a pyridyl radical. Radical dimerization furnishes a 4-4'-dihydrobiaryl (see drawing).

intermediate dimer

Aromatization to paraquat requires the loss of two hydrogen atoms and two electrons; the latter are being used to regenerate cyanide.

The mechanism is a bit speculative but consistent and reflects the catalytic use of cyanide.

Note: I would have liked to add a sketch for the mechanism but BKChem died on me several time while doing so.

  • $\begingroup$ I have no idea whether that is possible, but it isn't what happens here as the cyanide is used in catalytic amounts (certainly much less than the pyridinium salt). I've clarified the question to include this fact. $\endgroup$
    – matt_black
    Commented Jan 3, 2014 at 19:08
  • $\begingroup$ I think the proposed mechanism is (now) compatible with a catalytic use of cyanide. $\endgroup$ Commented Jan 3, 2014 at 19:25
  • $\begingroup$ Doesn't your mechanism require an oxidant? $\endgroup$
    – matt_black
    Commented Feb 3, 2014 at 20:21
  • $\begingroup$ Yes, it does. The excited singlet state of the N-methylpyridinium cation with its low-lying SOMO is a much stronger oxidant for the cyanide than its ground state. $\endgroup$ Commented Feb 3, 2014 at 22:00

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