I know that with a SN2 reaction mechanism this becomes (S)-2-methoxypentane, but with elimination this is trans-2-pentene. I know that elimination happens quickly when you apply heat. In this case we have a secondary alkyl halide so its possible to use SN2 or E2 due to methoxide being a strong nucleophile.

  • $\begingroup$ To be honest, I think it is very hard to decide as not enough information is provided. I think if the reaction temperature was given, it would help us find the answer much more easily. But yes, your deduction that it is either (S)-2-methoxypentane or trans-2-pentene is sound. $\endgroup$ – Tan Yong Boon Jun 4 '17 at 16:01

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