# Number of F-Br-F angle of 90 degree in BrF5?

I faced a question like this:

The number of $90$ degree $\ce{F-Br-F}$ angle in $\ce{BrF5}$ according to VSEPR theory is:

The answer is given $0$ or $8$. I know $\ce{BrF5}$ has $\pu{sp3d2}$ hybridization. But there is no $90$ degree $\ce{F-Br-F}$ angle in this geometry due to the lone pair electron in $\ce{Br}$. But I find no other alternative structure to present $8$ $\ce{F-Br-F}$ angle of $90$ degree.

Any hints?

• Please format your questions using mhchem. You've written over 38 posts, so by now you should be aware how to use proper formatting. Please respect other people's time by taking the trouble to make the post as readable as it can be. May 23 '17 at 8:10
• There is no such thing as sp³d² hybridisation, that is the main and principle shortcoming of VSEPR. The answer, however, is en.wikipedia.org/wiki/Square_pyramidal_molecular_geometry. May 23 '17 at 8:14
• Have a look at it's structure: i.stack.imgur.com/qDpYw.png May 23 '17 at 8:46