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Here is the reaction of $\ce{HCl}$ with $\ce{H_{2}O}$ I found on a website

$$\ce{HCl + H_{2}O -> H^{+}(aq) + Cl^{-}}(aq)$$ However, in my text-book, the reaction is given as

$$\ce{HCl + H_{2}O -> H_{3}O^{+} + Cl^{-}}$$ Can anyone tell me what's going on here ? Which one is correct ?

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  • $\begingroup$ See en.wikipedia.org/wiki/Hydronium $\endgroup$ – ManRow May 19 '17 at 11:43
  • $\begingroup$ Both are correct. Moreover, in fact both are the same. $\endgroup$ – Ivan Neretin May 19 '17 at 12:03
  • $\begingroup$ @IvanNeretin could you elaborate it a bit? $\endgroup$ – Imaginary Pumpkin May 19 '17 at 12:04
  • $\begingroup$ @IvanNeretin I think I have to disagree. Bare protons are way too much polarizing power to exist without binding to solvent molecules (in this case it's $\ce{H2O}$). $\endgroup$ – Pritt says Reinstate Monica May 19 '17 at 14:46
  • $\begingroup$ Odd that Community♦ redirected the duplicate to another duplicate. $\endgroup$ – Pritt says Reinstate Monica May 19 '17 at 14:48