I've given a question , 3-chloropyridine + NaNH2 gives out A . Compound A on further reaction with furan gives compound B.

What I think now , First step is simple elimination addition reaction . So A should be 3-Aminopyridine . Next step is little bit confusing to me. I think product B should be nucleophilic substituted at 2-position of Furan by -NH2 group of 2-amniopyridine .

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    $\begingroup$ Think you've got this wrong. I doubt sodamide displaces chloride from the 3 position (2 or 4 much more possible). I think it far more likely it is acting as a strong base. $\endgroup$ – Waylander May 14 '17 at 10:42
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    $\begingroup$ en.wikipedia.org/wiki/Aryne $\endgroup$ – orthocresol May 14 '17 at 12:20

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