# Reaction of 3-Chloropyridine

I've given a question , 3-chloropyridine + NaNH2 gives out A . Compound A on further reaction with furan gives compound B.

What I think now , First step is simple elimination addition reaction . So A should be 3-Aminopyridine . Next step is little bit confusing to me. I think product B should be nucleophilic substituted at 2-position of Furan by -NH2 group of 2-amniopyridine .

• Think you've got this wrong. I doubt sodamide displaces chloride from the 3 position (2 or 4 much more possible). I think it far more likely it is acting as a strong base. – Waylander May 14 '17 at 10:42
• en.wikipedia.org/wiki/Aryne – orthocresol May 14 '17 at 12:20