Geometries of SCl2(OCH3)2 and SF2(OCH3)2

I am not able to understand the difference between structure of $$\ce{SCl_{2}(OCH_{3})_{2}}$$ and $$\ce{SF_{2}(OCH_{3})_{2}}$$.

I am already well versed with Molecular Orbital and VSEPR theories. I found the geometries, but don't understand why they are:

Why is the $$\ce{F}$$ at axial positions and $$\ce{Cl}$$ on the other hand in equatorial positions? (I am not able to understand Bent's Rule to be straight-forward, I have read Wikipedia already.)

• May 11 '17 at 18:57
• As a general reminder: The involvement of d-orbitals into the bonding is one of the many shortcomings of VSEPR theory. The sp³d hybridisation simply is not evident (and it is not necessary) in the bonding of these molecules. I can't stress that enough. Textbooks which still rely on this explanation are outdated and desperately need revision. May 12 '17 at 7:47
• Ok, I think I understand it now..... Things became more clearer by Ron's answer to the question suggested above by Orthocresol (Thanks!) and I got to know that my textbook is outdated, cheers to Martin. May 13 '17 at 11:17
• @orthocresol I'm not sure that Bent's rule is straight forward to use here, and I am especially not sure, whether the given geometries are indeed correct. From my initial calculations, the lowest energy structure also has a co-linear arrangement of Cl-S-Cl. May 19 '17 at 12:54

Check the bond angles. The larger the angles around a bond, the more S character. Electronegative elements prefer higher P character(Therefore less the bond angles). Axial position has lesser bond angles.Hence higher electronegative element takes axial position.( F>O>Cl)

This concept however may not be applicable to every compound.