# Explain the selectivity in bromination of this compound with two substituted benzene rings

As I know, when $\ce{Br2/FeBr3}$ is added to acetophenone ($\ce{C6H5-CO-CH3}$), Br will substitute a H from the meta position which leads to 3-bromoacetophenone. So why doesn't a Br substitute a H from the right side benzene (connected to the carbonyl group)?

• The right side has got a carbonyl as a substituent, so the ring is deactivated towards electrophilic substitution. – Zhe May 11 '17 at 12:18