# Cyclohexene reduction reaction with hydrogen gas and ethanol [closed]

I have a following reaction (see below). I found the section of reduction and oxidation states in my book but there is nothing about cyclohexenes. I know that the double bond will be reduced in this reaction but what I have no idea what happens to those substituents. Why do they move around and what are their orientations?

• You know how reaction works, but not rotated molecule... Wow – Mithoron Apr 29 '17 at 20:48

$\ce{H2/Pd}$ is a reducing agent, and it acts so by adding hydrogen to the double bonds. Alkenes are converted to alkanes. This proceeds via a concerted pathway, so rearrangements due to carbonation shifts do not occur. Now I think you can proceed from here.
The reaction with $H_2/Pd$ is one of the ways to reduce alkenes to alkanes. This takes place over the Palladium surface which has $H$ adsorbed on it. Hence we can think of cis addition in this case.