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Whenever there a question comes to find the pH of the given solution, I always gets confused to identify the solution if it is a buffer solution or whether it will undergo salt hydrolysis .

Can anybody explain this to me?

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closed as unclear what you're asking by Todd Minehardt, airhuff, Wildcat, ron, Buttonwood Apr 21 '17 at 21:51

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    $\begingroup$ This would be much easier to answer if you could edit in a couple examples. $\endgroup$ – airhuff Apr 21 '17 at 19:56
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When you have just a salt left with either [or even both] of its ions coming from a weak acid/base, it is a case of SALT HYDROLYSIS. I mean to say no free acid or base is left. e.g, 100 mL 0.1 N CH3COOH + 100 mL 0.1 N NaOH ---> 100 mL 0.05 N CH3COONa This need to be solved by SALT HYDROLYSIS

While if you have a salt(from the same weak acid/base) + a weak acid or base present, i.e., both are present, it would be a case of BUFFER.

200 mL 0.1 N CH3COOH + 100 mL 0.1 N NaOH ---> 100 mL 0.033 N CH3COONa + 100 mL 0.033 N CH3COOH (left unreacted) This need to be solved by BUFFER

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  • $\begingroup$ Avoid answering questions with low votes. $\endgroup$ – Pritt Balagopal Apr 30 '17 at 2:49

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