0
$\begingroup$

I would like to ask how many valence electrons took part in creating chemical bond in $\ce{OH-}$? Is the minus related to $\ce{O}$ or to $\ce{H}$? Are there any spare valence electrons which didnt take part in creating chemical bond in $\ce{OH-}$?

$\endgroup$
1
$\begingroup$

enter image description here

In the photo the orange electrons are non bond electrons.
And the black electrons are bond electrons.

There are 2 electrons took part in creating chemical bond in $\ce{OH}$. The first one is from oxygen.
The second is from hydrogen.

This kind of bond is called "Covalent bond". For more about Covalent bond : https://en.wikipedia.org/wiki/Covalent_bond

The minus is related to the black and white electrons that are free (in Oxygen).

The white electron is come from other element.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.