$$\ce{C5H11Cl + C4H9I + 2Na ->}$$ Is this possible in a Wurtz reaction? I want to add 2 different alkyl halides with two different halogens. I'm curious if two different types of halogen on the alkyl reactants is possible.
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$\begingroup$ This is going to be pretty messy. Each reagent will react not only with the other one, but also with itself. $\endgroup$– Ivan NeretinApr 11, 2017 at 14:48
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$\begingroup$ As a side note, I would also mention the Corey-House synthesis, a method to couple asymmetrical halides. We transform one of the alkyl halides into a lithium dialkyl cuprate (R2CuLi) and react it with the other alkyl halide (R'X). The result would be a alkane R-R'. $\endgroup$– Pritt says Reinstate MonicaApr 12, 2017 at 2:07
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$\begingroup$ There are going to be issues concerning separation as the products will have nearly same boiling points making fractional distillation difficult. $\endgroup$– RaghavApr 12, 2017 at 3:55
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1 Answer
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The alkyl groups mentioned could be primary, secondary or tertiary
The last one's will not be going by Wurtz reaction (these will rather undergo elimination to give alkenes); only primary & secondary can.
Even here, we can have a mixture of products:
