In a step wise approach, based on the NMR data provided:
The broadband decoupled 13C NMR spectrum accounts for six magnetically different nuclei. (2-Pentanone drawn by you is not consistent with that, its carbon atoms would yield at maximum five signals.) The four signals in the interval of about 120 to 140 ppm could be carbon atoms of an aromatic ring; the two between 40 to 60 could be by an alkyl chain adjacent to some electron withdrawing group.
The 1H NMR spectrum displays a multiplet in the "aromatic region" worth 5 H. There is a broad singlet around 4.5 ppm; shape and to some extend location of this signal may refer to an exchangable proton by an OH group (this again is not explained by your first attempted attribution).
Still refering to the 1H NMR spectrum, there are two signals like for an alkyl chain adjacent to an electron withdrawing group; yet their chemical displacement ($\delta$) is a bit too high to be just a normal alkyl chain. This is equally consistent with the two signals in the alkyl region of the 13C NMR spectrum, too.
Mass spectroscopy mentions a molecular ion, correlated to a molecular mass of 122 g/mol.
How is this consistent with the IR data provided? An absorption in the range of 3600 to about 3200 1/cm is typical for free OH, like in the instance of alcohols. In this particular example, with (perhaps arbitrary selected) absorptions mentioned by their position (only), there is little of information you may extract. Maybe for educational purpose in tune of "not every single information adds to knowlegde promptly useable".
Why – on purpose – a different compound like the isomeric p-ethyl phenol does not represent a valid answer?
The 1H NMR spectrum for this compound would be different. The pattern in the alkyl region were a quartett (accounting for two protons) and a triplett (accounting for three protons). Very often, the para-subsitution pattern would split the signals in the aromatic region into two dublets of equal intensity, accounting each for two magnetically equivalent protons.