# Reaction of concentrated nitric acid react with metallic lead?

Here is my work:

Concentrated $\ce{HNO3}$ should first decompose into $\ce{NO2}$, $\ce{H2O}$ and $\ce{[O]}$. Nascent oxygen should combine with $\ce{Pb}$ to form $\ce{PbO}$. Now $\ce{PbO}$ should neutralize acid to form $\ce{Pb(NO3)2}$.

Therefore, the net products would be lead nitrate, $\ce{NO2}$ and $\ce{H2O}$.

Is this right?

Well, you were going along the right track.... just one correction. The products will be Pb(NO₃)₂, NO₂ and H₂O. Nitric acid is a very powerful oxidizing agent. It oxidized H₂ to H₂O.

• Oh! I forgot to add O. I have added it now. – Aumkaar Pranav Shukla Apr 11 '17 at 14:10

Lead when reacted with nitric acid forms lead(II) nitrate, nitrogen oxide and water.

According to Wikipedia:

Lead(II) nitrate can be obtained by dissolving metallic lead in aqueous nitric acid:

$$\ce{Pb + 4 HNO3 → Pb(NO3)2 + 2 NO2 + 2 H2O}$$

Since the solvent is concentrated nitric acid (in which lead(II) nitrate has very low solubility) and the resulting solution contains nitrate ions, anhydrous crystals of lead(II) nitrate spontaneously form as a result of the common ion effect.

According to webelements:

Lead reacts slowly nitric acid, $\ce{HNO3}$. Nitrogen oxides are formed together with lead(II) nitrate, $\ce{Pb(NO3)2}$.