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How do you determine the theoretical concentration of an acetic acid solution in mol dm-3 of vinegar that is 5% acetic acid, knowing that the density of vinegar is 1.000g cm-3?

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    $\begingroup$ Actually at 15 C the density of 5% acetic acid is 1.0067 g/ml. books.google.com/… $\endgroup$ – MaxW Mar 29 '17 at 19:52
  • $\begingroup$ Vinegar is not defined as a solution of 5 % acetic acid at 15 C. Vinegar comes in many different varieties with different densities, including solutions of 3, 4, 5 or 6... % of acetic acid. Vinegar usually also contains other things than acetic acid and water. The question state the density of the actual vinegar to be 1.000 g/ml. So, what´s the problem with that? I do not understand in what way you think your comment would help the questioner. $\endgroup$ – Bive Apr 1 '17 at 22:09
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1000 ml of vinegar will contain 0,05*1000 = 50 g of acetic acid. 1000 g of the vinegar will have a volume of 1.000 liter. Mole weight of acetic acid: 60.05 g/mole => 50/60.05 = 0,83 mole => Concentration of acetic acid: 0.8 M

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  • $\begingroup$ Please explain why my answer above was considered a "downwrote". $\endgroup$ – Bive Mar 31 '17 at 22:39

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