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I read one of the answers for a similar question, According to that it is due to the hemiacetale group converting into a carbonyl group. I don't get why the same thing can't be applied to sucrose though.

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marked as duplicate by Klaus-Dieter Warzecha, Todd Minehardt, airhuff, Loong Mar 12 '17 at 5:59

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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if youre looking for a rather unsophisticated answer.....it would go as....for a pyranose ring to open up...it needs to have a hemiacetal group ...such a group is present in maltose and absent in sucrose...the same thing cant be applied to sucrose as it dosent have a hemi acetal group...please check the structure again...(needs a C-OH linked to the ether linkage that holds together both rings..i guess thats how it goes in simple terms...hopefully i answered your question

P.S:The link given in the answer above mine has a better detailed explanation

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