The plot is from Wikipedia, where important/helpful links to the source information can be found, and is worth a look.
A similar and more detailed plot can be found on this page of Martin Chaplin's famous site on all things water. I can't recommend that site highly enough! The plot is shown below, and note that it's using centimeters instead of meters.


This section in Wikipedia gives us a clue. It says
Absorption coefficients for 200 nm and 900 nm are almost equal at 6.9 m−1 (attenuation length of 14.5 cm).
Those numbers are reciprocal, and reading the links shows the terms refer to $1/e$ lengths, natural units.
Both this plot and Wikipedia's are intended to give a global electromagnetic perspective rather than detailed quantitative information. I believe there really is a peak near 2 microns where a 1 cm cuvette of pure water would be nearly opaque. Remember it's using natural units, not 10, so ya, if you sit on that peak, using:
$$T = exp\left(-h(cm) \ \times \ ~100 (1/cm)\right)$$
and plugged in a 1 cm optical path, you'd get a transmission of 4E-44, or basically zero. You many find that there are different cuvettes with substantially reduced optical paths that can be used in this case. A sub-1 millimeter path length cuvette might do better.
However, a little bit above or below 2 microns, the attenuation drops to only 10 per centimeter, which gives a transmission of about 5E-05 for a standard 1 centimeter path length cuvette, and a quality instrument would have no problem measuring that with a suitable detector and integration time.
If you're interested in going farther, I'd recommend you find a plot that is nod drawn with such thick lines, or find tabulated data and plot it in detail by yourself. There are some numbers just for example in this 1975 paper but the hard short-wavelength cutoff at 2 microns may obscure the peak there. However let's look at the properties near 3 microns.
At 2.959 microns, $n, k = 1.329, 0.292$. Putting that into here
$$\frac{E}{E_0} \ = \ exp\left(j \left(n + jk\right) \frac{2\pi}{\lambda} x \right) $$
puts the electric field attenuation of 1 centimeters at $exp(-6200)$. You need to square to get transmitted intensity, so doubling the argument gives 12,400/cm or 1.24/um, which very nicely matches the "3 micron peak" in the plot, especially the inset in red(see below). This is really a mixture of states in the circa 3400 cm${}^{-1}$ water vibrational spectrum. Also, when you read, make sure you keep track of the isotopic mixture being discussed. H2O and HDO differ profoundly in their infrared optical properties.
All is well, and water continues to be amazing, profound stuff!