# Problem in Colour in Cerium (IV)Sulphate due to charge transfer

My text says that $\ce{Ce(SO4)2}$ is coloured due to charge transfer spectra. It also gives other examples such as $\ce{KMnO_4}$ and $\ce{K_2Cr_2O_7}$, to which I agree but when I read the conditions for charge transfer spectra to take place it says

1. +6;+7;+8 show it more
2. if the central metal atom is diamagnetic but still if compound is showing colour.

I see $\ce{Ce}$ in its +2 state and configuration $\ce{[Xe] 4f^1 5d^1 6s^0}$ doesn't show 1st the conditions then where am I going wrong?

• ohh! no it should have been $Ce(SO_4)_2$ ; But still it doesn't hold the first condition true why? – Physicsapproval Mar 3 '17 at 15:22
• – Nilay Ghosh Mar 12 '17 at 13:00
• I want to know why both conditions in my text are not true simultaneously? why? – Physicsapproval Mar 13 '17 at 3:55