My text says that $\ce{Ce(SO4)2}$ is coloured due to charge transfer spectra. It also gives other examples such as $\ce{KMnO_4}$ and $\ce{K_2Cr_2O_7}$, to which I agree but when I read the conditions for charge transfer spectra to take place it says

  1. +6;+7;+8 show it more
  2. if the central metal atom is diamagnetic but still if compound is showing colour.

I see $\ce{Ce}$ in its +4 oxidation state and configuration $\ce{[Xe] 4f^1 5d^1 6s^0}$ doesn't show 1st the conditions then where am I going wrong?

  • $\begingroup$ ohh! no it should have been $Ce(SO_4)_2$ ; But still it doesn't hold the first condition true why? $\endgroup$ Commented Mar 3, 2017 at 15:22
  • $\begingroup$ Related: chemistry.stackexchange.com/questions/34733/… $\endgroup$ Commented Mar 12, 2017 at 13:00
  • $\begingroup$ I want to know why both conditions in my text are not true simultaneously? why? $\endgroup$ Commented Mar 13, 2017 at 3:55
  • $\begingroup$ Cerium(IV) is not $\ce{[Xe] 4f^1 5d^1 6s^0}$. With $58-4=54$ electrons it must be $\ce{[Xe]}$ only, so diamagnetic and yet colored. $\endgroup$ Commented Feb 15, 2023 at 23:44


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