0
$\begingroup$

It is written in my textbook that :

Alkyl halides are used as solvents for relatively non polar compounds.

Alkyl halides are themselves polar with carbon having delta positive charge and halide having delta negative charge. If polar compounds are dissolved in them, then there will be more interactions between the compound and alkyl halide. The polar compound should dissolve in it.

What do they mean "relatively non polar compounds are soluble in alkyl halides" ? How will non polar compounds become soluble and why the textbook does not mention solubility of polar compounds?

$\endgroup$
  • $\begingroup$ Alkyl halides are less polar than they seem. $\endgroup$ – Ivan Neretin Mar 3 '17 at 13:41
  • $\begingroup$ But "still" they are polar. How will non polar compounds be soluble in them at all? $\endgroup$ – Arishta Mar 3 '17 at 14:38
  • $\begingroup$ OK, they are even less polar than you seem to think now. $\endgroup$ – Ivan Neretin Mar 3 '17 at 14:53
  • $\begingroup$ I thought they were polar based on their electronegativity diffrence which is around 0.5 in Pauling scale. $\endgroup$ – Arishta Mar 3 '17 at 15:00
  • $\begingroup$ Like I said before, electronegativity is hardly a precise measure of anything. $\endgroup$ – Ivan Neretin Mar 3 '17 at 15:01
1
$\begingroup$

Polarity is relative. Dipole moment (macro scale) and dielectric constant of the solvent (molecular scale) are probably the most decisive. Water has ε~80, ethanol 25 and DCM is "only" 9. By comparison toluene, benzene or tertachlormethane have ε~2. The last example also illustrates why differences in electronegativity are not enough. Being symmetric (Td) tetrachloromethane has dipole moment of zero, even if there is a big difference between electronegativity of carbon on chlorine.

$\endgroup$
  • $\begingroup$ I understand that more is the dielectric constant, more is the force applied by the solvent molecules on the charged particles. But I don't understand how dielectric constant affects the process of dissolution? $\endgroup$ – Arishta Mar 3 '17 at 18:29

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.