What is the resultant pressure if 0.6 mol of ideal gas at 273 K and 1.18 atm in a closed container of constant volume is heated to 563 K? Answer in units of atm


We have PV=nRT (where symbols have there usual meaning.)

You see V is constant as the container doesn't change or deform ( as you mentioned)

so thinking that way PV/nRT=constant as moles are constant and not leaking R is universal gas constant . so ;

P/T is constant then $P_1/ P_2 = T_1/T_2$

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  • $\begingroup$ What about the moles though? $\endgroup$ – Sid Puranik Mar 1 '17 at 5:02
  • $\begingroup$ they would just be constant provided there's no leakage $\endgroup$ – Physicsapproval Mar 1 '17 at 5:03
  • $\begingroup$ Oh I see. So would you just plug it in to be: 1.18/273 = P2/563 $\endgroup$ – Sid Puranik Mar 1 '17 at 5:04
  • $\begingroup$ So would it be 2.43? $\endgroup$ – Sid Puranik Mar 1 '17 at 5:05
  • $\begingroup$ hmm; just math , just calculation :) $\endgroup$ – Physicsapproval Mar 1 '17 at 5:09

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