# How to calculate molality, molarity and mole fraction given density (g/mole)?

Calculate the molality, molarity and mole fraction of a $\ce{CuSO4}$ in a 17% m/m aqueous solution (density of the solution is 1.367 g/mole)

I did .17 * 1.367 to find grams of $\ce{CuSO4}$

and .83 * 1.367 to find grams of $\ce{H2O}$

Then used to them calculate:

molarity = 0.00146 M

molality = 1.287 m

Mole fraction = 0.023

I'm wondering if I'm doing it right?

Now, density = Total weight/Total moles = 100/(0.268 + x) = 1.367 where x is moles of solvent, from here you will get x = 72.8849
Thus, mole fraction of Cu is 0.268/(0.268+72.8849) = 0.00366
Molality = Moles of solute/Weight of Solvent(in Kg) = 0.268/0.083 = 3.229 m