This is an updated question:
I don't have a very strong background in biophysics, but I want to understand the theory behind $\ce{NAD+}$ and $\ce{NADH}$ absorbance and fluorescence.
Background: I understand that the additional hydrogen that $\ce{NAD+}$ gains to form the reduced $\ce{NADH}$ results in the molecule being able to absorb light at $\pu{340nm}$. And that only the reduced $\ce{NADH}$ is able to produce fluorescence. This is also the property which is explored when studying, e.g., enzyme kinetics - if the enzyme binds $\ce{NADH}$.
Question: The oxidized form, $\ce{NAD+}$, still has an aromatic ring - why is it that it is not able to fluoresce? Why, in a nutshell, is the transfer of the hydrogens causing fluorescent in $\ce{NADH}$ and such a big change in absorbance spectrum?
Also, perhaps a bit naive question, but why is it fluorescence better to measure than absorbance?
I have tried to look for articles (the old and original) that explores these properties, but I can't seem to find any that purely speak about the spectroscopic properties.