1
$\begingroup$

enter image description here

Why is E2 reactivity rate of the second compound said to be faster than the first compound even though the transition state is same? My teacher said that in E2 more hindrance implies faster reaction. In the first compound H atom is more hindered due to methyl group. Even then why is the reactivity of the second compound in presence of a strong base, said to be faster?

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy