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I'm looking at some high precision quantum chemistry methods like Coupled Cluster (CC) and FULL CI (FCI).

It seems both CC and FCI start from Hartree-Fock and then excite the electron to higher states.

If I understand correctly, CC uses an exponential operator to raise the states of the electron while FCI explicitly calculates the coefficients of each determinants.

What makes the difference between CC and FCI? Can someone give an intuitive explanation? Thanks.

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    $\begingroup$ Related but solidly different, this answer discusses FCI as it relates to CASSCF/RASSCF. $\endgroup$
    – hBy2Py
    Feb 5, 2017 at 4:30
  • $\begingroup$ Well I am sure one of the more experienced users will weigh in on this, but given that I have recently started reading into this stuff myself , I would say configuration interaction is not size extensive (say for 2 non-interacting $\ce{H2}$s), while CCSD is exact for N non-interacting $\ce{H2}$. My 2 cents. $\endgroup$
    – getafix
    Feb 5, 2017 at 4:30
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    $\begingroup$ @getafix FCI is also horrifically expensive for all but the tiniest of systems. To be clear, AFAIK full CI (where every single orbital is correlated) is actually size extensive. It's the truncated versions that are not. $\endgroup$
    – hBy2Py
    Feb 5, 2017 at 4:33
  • $\begingroup$ @hBy2Py I see. Would you happen to know how the two methods scale ? $\mathcal{O}(N^6)$ or $\mathcal{O}(N^7)$ or higher? $\endgroup$
    – getafix
    Feb 5, 2017 at 4:36
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    $\begingroup$ @getafix Pretty sure FCI is O(N!) or higher. Not sure about CC. Would have to pull Szabo and Ostlund out. $\endgroup$
    – hBy2Py
    Feb 5, 2017 at 4:45

1 Answer 1

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Full Coupled Cluster (FCC) vs. Full Configuration Interaction (FCI)

The main theoretical difference is the way excitations are used. "Excitation" refers to putting one or more electrons in higher orbitals than the "reference" calculation, which is often a Hartree-Fock calculation, would. CI uses a "simple", linear excitation operator, whereas CC uses a more complicated, exponential one. One can think of CI as a sum of excitations while CC results in a product of excitations. Symbolic equations for the wave function ($\Psi$) ansatz of either method read: $$ \Psi^{\text{CI}} = (1 +C_1+C_2+C_3+...) \Psi^{\text{HF}} \\ \Psi^{\text{CC}} = \exp(T_1+T_2+T_3+...) \Psi^{\text{HF}} \\ = (1 +T_1+T_2+T_3+\frac{1}{2}T_1^2+\frac{1}{2}T_2^2+T_2T_1+\frac{1}{2}T_3^2+...+\frac{1}{6}T_1^3+...) \Psi^{\text{HF}} $$ In CI, the excitation operator is often denoted $C$ and the prefactor of determinants are called CI coefficients, whereas CC uses $T$ and "amplitudes". In either, the subscript refers to the number of excited electrons. For "full" calculations, that is, calculations that take into account every possible excitation, the results of CC and CI will be identical.

Full calculations are too expensive for all but the smallest systems, because the cost rises as $O(N!)$, where $N$ is some measure of the system size involving electron number and basis set size. For this reason, one typically decides to "truncate" the excitations to lower the cost.

Single-reference Truncated CC vs. Single-reference Truncated CI (this is what CC and CI commonly refer to)

Truncation first involves collecting the excitations into "classes" of excitations. Within a class, one gets similar cost and hopes for similar contributions. Thus, one may sort of gauge the cost and accuracy of the calculation. Standard ways of doing this have evolved, and this is what CCSD, CCSD(T), CISD etc. refer to. CASSCF/RASSCF can be categorized like this, as well.

With truncation, another difference between CI and CC arises: CC is no longer variational and CI is no longer size-extensize. Variationality is the property that the resulting energy has the true energy (of the given basis set) as a lower bound - one approaches the energy monotonically from above as more excitations become involved. Size-extensivity is the property that two identical systems at infinite separation from each other yield twice the energy of a single system. The latter property is thought of as the more important one, mainly because of its implications for closer, interacting systems. Variationality is also less of a concern because finite basis sets must be used, thus, one is typically far above the true energy anyway.

Another technical difference is that truncated CC and CI lead to different equations, for which different methods of solving have been developed. Overall, CC implementation is, or at least used to be, more difficult. Properties other than the total energy can also be more difficult to implement.

Scaling of CC and CI

Basically, when truncation is performed at similar levels, the two methods scale the same, but the prefactor may be different - this also depends on the quality of the implementation. For reasons stated above, CC has been worked on more intensively since, say, the mid 1990s. So, CISD and CCSD scale similarly, CISDT and CCSDT would as well. Bottom line: CCSD(T) will still be affordable for molecules where full CI would require specialized implementation on a dedicated supercomputer.

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    $\begingroup$ The reference wave function does not have to be a Slater determinant from a Hartree-Fock solution; that's just convenient to use. The former gives rise to multiconfigurational approaches. An early attempt of correcting CISD for size-extensivity was the Davidson Correction. Another approach is QCISD. It actually is hard to believe that CISD scales similar to CCSD, as the latter has exponentially more terms. You should review the edit, your Taylor expansion is incomplete. $\endgroup$ Feb 10, 2017 at 8:44
  • $\begingroup$ To @Martin-マーチン 's comment: Yes, other references are possible, (including DFT-based determinants). The answer will deal with single-reference. Frank Jensen (Introduction to Computational Chemistry, 2nd ed., Wiley) [FJ] notes that the Davidson correction is not correct for two-electron systems. QCISD was shown to be an approximation to CCSD [FJ]. Can you be more specific concerning the Taylor expansion? $\endgroup$
    – TAR86
    Feb 10, 2017 at 17:29
  • $\begingroup$ My comment was in no way critique, just an extension, maybe asking for some more explanation for the scaling part. I remember from my courses on post-HF methods that even though CCSD(T) is more expensive than CISD(T), we use it since it recovers more of the correlation energy. As for the expansion, I quite liked it how you grouped the clusters according to their excitation $= (1 +T_1+(T_2+T_1^2)+(T_3+T_2T_1+T_1^3)+...)$, now it looks quite odd since it does not have much resemblance with the Taylor expansion $\exp\{ \mathbf{T} \} = \sum_n\frac1{n!} \mathbf{T}^n$, i.e. the terms appear random. $\endgroup$ Feb 14, 2017 at 5:00
  • $\begingroup$ I apologize for the curt comment I gave before, it was a lot to get to. Note that scaling is only one part of the cost, the other is the prefactor, which may easily be higher for CC and is also very much implementation-dependent. An edit of the Taylor expansion was suggested by other users - the expansion you gave can be found in most books, anyway. Thank you for your suggestions! $\endgroup$
    – TAR86
    Feb 14, 2017 at 18:02

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