Order for solubility of isomeric alcohols in a book was given as:
Primary alcohol >Secondary alcohol >Tertiary alcohol After this I found a question as :
1) Which is more soluble in water?
Ans:- (a) & the reason was that (a) has more compact alkyl portion than (b). But as (a) is a tertiary alcohol while (b) is a secondary one ,so according to the given order answer should be reverse.
Also while comparing
2-methyl-2-propanol & 1-butanol
Here 1-butanol had higher solubility which matched the given order. I am not understanding what's wrong about the first case. Please explain me.