I'm looking at the reaction shown below which uses a ruthenium catalyst:

enter image description here

I am confused because the ruthenium catalyst which is used in the reaction should be Z selective due to the features on the catalyst because the adamantyl group favours the side bound pathway i.e. the Z isomer and the di-iso-propyl phenyl group blocks the path to the E alkene.

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    $\begingroup$ Did you perform this reaction and get that result? Are you looking at some publication that publishes this? $\endgroup$ – Jan Jan 19 '17 at 14:12
  • $\begingroup$ Is there an error in the reaction? The reactant has 5 carbons, and the product has 8. If this is supposed to be a dimerization, what happens to the two missing carbons? $\endgroup$ – Curt F. Jan 19 '17 at 14:15
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    $\begingroup$ @CurtF. There doesn't appear to be a mistake. This is standard olefin metathesis. Ethylene is the assumed by-product. $\endgroup$ – Zhe Jan 19 '17 at 14:47
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    $\begingroup$ @CurtF. They did give out 3 Nobel Prizes for it in 2005... $\endgroup$ – Zhe Jan 19 '17 at 18:38
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    $\begingroup$ Please add/cite your source then =) $\endgroup$ – Jan Jan 19 '17 at 19:24

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