2
$\begingroup$

What can be added to liquid $\ce{CO2}$ to lower the electricity needed to crack $CO_2$ ? Answer: Zirconium dioxide

What form and temperature of $\ce{CO2}$ is best to crack with or without Zirconium dioxide?

https://space.stackexchange.com/questions/19755/can-carbon-dioxide-be-broken-down-by-electrolysis

enter image description here

|improve this question
$\endgroup$

closed as unclear what you're asking by hBy2Py, Todd Minehardt, bon, Klaus-Dieter Warzecha, Ivan Neretin Jan 15 '17 at 7:41

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • 2
    $\begingroup$ Unfortunately, none of those sentences make any sort of chemical or electrochemical sense to me. Baking soda doesn't break water down in any manner I'm aware of. What do you mean by "break CO2 down?" Electrolysis requires an electrolyte; there do exist solid electrolytes, but they are always ionic compounds, not covalent ones like CO2, so no, electrolysis will not work in solid CO2. Neon gas will not carry electric current at all, unless you apply such a high voltage that you ionize it into plasma. $\endgroup$ – hBy2Py Jan 14 '17 at 17:12
  • 1
    $\begingroup$ I'm pretty sure @hBy2Py adequately answered this, so it can't possibly be unclear. $\endgroup$ – M.A.R. Jan 14 '17 at 18:12
  • 1
    $\begingroup$ @M.A.R. Especially after looking at the linked question on SX.SE, I think there's an answerable question lurking in there somewhere -- I just for the life of me can't figure out what it is. Muze, you might want to head to the Chem.SE main chat to get some help clarifying what you're looking for, and then edit the question accordingly. $\endgroup$ – hBy2Py Jan 14 '17 at 18:33
  • 2
    $\begingroup$ @hBy I think it's the one in the title. $\endgroup$ – M.A.R. Jan 14 '17 at 18:35
  • 1
    $\begingroup$ @Muze Ok, so ... are you assuming you've got the CO2 pressurized and cooled such that it's a liquid? $\endgroup$ – hBy2Py Jan 14 '17 at 19:29