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enter image description here DeltaH for process is positive and deltaS is negative. Then by thermodynamics,deltaG for process must be positive at all temperatures. Then how is ozone formation spontaneous?

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    $\begingroup$ Why do you think it is spontaneous. $\endgroup$ – Greg Jan 7 '17 at 11:54
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    $\begingroup$ '...a slow dry stream of oxygen is passed through an [electrical] discharge...' (the picture cut off at the end of the line). If an electrical current is required then the process isn't spontaneous at all, you're putting energy in $\endgroup$ – NotEvans. Jan 7 '17 at 13:04
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    $\begingroup$ Do you regularly notice oxygen in the air spontaneously converting into ozone? $\endgroup$ – porphyrin Jan 7 '17 at 13:24
  • $\begingroup$ How long would it take you to either type out the contents of the text in your image or re-image it so the rest of us can see it? I will then probably spend at least that much time working towards an answer for you. I cannot promise that I will come up with an answer good enough for posting, but I'll try ;-) $\endgroup$ – airhuff Jan 11 '17 at 22:57
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It seems reasonable to suspect that some O2 molecules will dissociate in the discharge. Some of the resulting atoms will bond to other O2 to form O3 instead of recombining. To evaluate the thermodynamics of this process, one should therefore start at atomic oxygen.

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