5
$\begingroup$

Can whatever is special about quasicrystals be understood at A-Level standard or slightly above it? The material I saw online is either too layman or too advanced for me to follow. What practical uses do they have and why does their structure lead to the properties that allow them to have these practical uses?

$\endgroup$
  • $\begingroup$ For those who don't know: A-level students are 16-18 years old. So advanced high school chemistry equivalent. $\endgroup$ – Ali Caglayan Jun 11 '15 at 1:18
4
$\begingroup$

It's hard to know exactly what “level” you want address, as the Wikipedia entry seems a decent introduction to me. But in any case, here's what I consider “special” about quasicrystals:

From the fundamental point of view:

  • Though they are regular (they are formed by symmetry operations that allow them to repeat throughout space), they are not periodic (the symmetry operations are not purely translations). Although there's nothing inherently “wrong” or “impossible” about that from theoretical physics and chemistry, it goes against the classical classification of solids: crystalline or amorphous.
  • Though hundreds of quasicrystals have been synthesized, there is only naturally occurring quasicrystal phase (icosahedrite)!
  • All quasicrystals are metal alloys (most of them being binary or ternary intermetallic alloys): given that there are other types of crystalline solids, why aren't there non-metallic quasicrystals?

Regarding applications:

  • Quasicrystals have found, so far, few practical and industrial applications. In these applications, they are used as other alloys would, and do not have any “magic quasicrystal property”.
  • One specific feature they have, though, is that quasicrystals tend to be rather strong alloys and that they age well, due to the way they are synthesized
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.