In the below reaction (reaction of 1-bromo-2-phenoxyethane with KOH at hugh temperature):
$$\ce{Ph-O-CH2-CH2-Br ->[\ce{KOH}][200\ ^\circ C]P}$$
According to me KOH will help in displacing bromide ion and making a carbocation. This carbocation would be attacked by the double bonds of the benzene ring. So the product should be benzotetrahydrofuran:
But the product is given as phenoxyethene (phenyl vinyl ether):
I could not understand how is this possible.