I am trying to understand why the red Br doesn't react? Is it because there can't be a flip of groups? Or steric hindrance?

Thank you!

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Backside attack on the red bromide is not possible. The rest of the norbornyl skeleton completely blocks the trajectory required for $\mathrm{S}_{N}2$ reaction.

  • $\begingroup$ Thank you for your answer! If possible, I would like to ask you this question: would the reaction if there were no bridge in the middle? Thank you! $\endgroup$
    – Johnathan
    Dec 17 '16 at 23:40
  • 1
    $\begingroup$ Yes. Because then, it would just be cyclohexane. As long as you could access the conformation where the red bromide group is axial, you could have a productive substitution reaction. $\endgroup$
    – Zhe
    Dec 18 '16 at 1:23
  • $\begingroup$ Excellent answer by Zhe. I'd also like to point out that the red Br is on a tertiary carbon anyway - makes SN2 nearly impossible. $\endgroup$ Dec 18 '16 at 7:16

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