# What product will be produced when a sucrose and potassium nitrate mix burns? [closed]

What product will be obtained get when a sucrose and potassium nitrate mix, which are the ingredients for smoke bomb, are burned in a combustion container?

$$\ce{KNO3 + C12H22O11 -> ?}$$

## closed as off-topic by ashu, Ben Norris, Philipp, bobthechemist, user467 Oct 11 '13 at 0:21

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You will get potassium carbonate ($$\ce{K2CO3}$$), carbon dioxide ($$\ce{CO2}$$), water ($$\ce{H2O}$$), and nitrogen gas ($$\ce{N2}$$): $$\ce{48KNO3 + 5C12H22O11 -> 24K2CO3 + 36CO2 + 55H2O + 24N2}$$
$$\ce{9.6 KNO3 + C12H22O11 -> 4.8 K2CO3 + 7.2 CO2 + 11 H2O + 4.8 N2}.$$
Therefore $$\pu{970 g}$$ $$\ce{KNO3}$$ and $$\pu{342 g}$$ sucrose, which is $$74\%$$ $$\ce{KNO3}$$ and $$26\%$$ sucrose. This produces $$\pu{662 g}$$ of potassium carbonate.