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I have no problem with identifying whether a given molecule has geometrical isomerism if it's not cyclic. But cyclic compounds are confusing for me. For eg: How to check whether the following molecule posses geometrical isomerism?

enter image description here

My thoughts: For a molecule to show geometrical isomerism different molecules should be attached to the double bonded carbons. So, I'm sure that geometrical isomerism(if it is present) is along the double bonded carbons. But, how to check whether different groups are attached to it when the double bonded carbons are the part of a cycle?

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Two ways to think about it:

  • Intuitively: Take one side of the double bond (say, the sulfur-containing one) and imagine rotating it by 180° (so what was up is now down, in your drawing). Is this molecule the same? If it is, then you don't have isomerism. If the procedure gives a new, different molecule, then you have isomerism.
  • More formal: use the Cahn–Ingold–Prelog rules to rank both sides of the two carbon atoms of the double bond. If priorities are different, then you have different isomers (and you can actually assign them a name.

In your particular example, the compound has another isomer, and the one you have drawn has the (E) configuration.

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  • $\begingroup$ I just read the Wikipedia article on Cahn–Ingold–Prelog rules. Can you give me an example on how to apply those in a cyclic compound? They say making a tree like structure and introducing ghost atoms. Can you please show an example? $\endgroup$ – Rajath Krishna R Oct 3 '13 at 10:33
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    $\begingroup$ @RajathKrishnaR sorry, this is really undergrad-level chemistry, and you will find plenty of explanations in any textbook… the site's goal is to help with specific questions, not to write courseware! $\endgroup$ – F'x Oct 3 '13 at 10:46

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