While learning about how batteries work I have encountered the following notation for a Li-ion cathode: $\ce{Li_{0.5}FePO4}$.[1]
According to Wikipedia, the subscript number in a reaction equation represents the number of atoms in a molecule. But what does the $0.5$ represent? Is it a fraction of atoms in a molecule?

Also, $\ce{LiFePO4}$ is a cathode. I would expect that for a fully charged battery, the anode is populated with all the $\ce{Li}$, therefore the cathode should be $\ce{FePO4}$, right? I can also understand that some $\ce{Li}$ gets stuck in the cathode, but then I read somewhere that a fully charged battery, the cathode is $\ce{Li_{0.5}FePO4}$.

I have added an exaggerated sketch for what I imagine the system would be.

enter image description here

I know that the structure of $\ce{Li_{0.5}FePO4}$ is more complex than this, but this is only a hypothetical sketch. Also, please note that I don't have a background in chemistry, so any additional material that can help me understand the concept better is greatly appreciated.


  1. Tan, H.; Fultz, B. Rapid Electron Dynamics at Fe Atoms in Nanocrystalline Li0.5FePO4 Studied by Mössbauer Spectrometry. J. Phys. Chem. C 2011, 115 (15), 7787–7792 DOI: 10.1021/jp200127b.
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    $\begingroup$ Have you understood how Li-Ion batteries work? The Li content is variable, and in practice always substoichiometric. $\endgroup$
    – Karl
    Commented Nov 20, 2016 at 11:29
  • $\begingroup$ I think I have an okay understanding of the batteries. I understand that there are structural changes, diffusion and potential differences. And yes, I know that the Li content is variable, that's why I would have expected that for a fully charged battery, all the Lithium ions would be in the anode, leaving the cathode "empty". But I also understand that there are some residual Li-ions that stay in the cathode. I'm trying to link this to chemical reactions. And as I said, I expected that the cathode would be FeFO4 as seen here: esl.ecsdl.org/content/9/3/A110/F2.large.jpg $\endgroup$
    – Physther
    Commented Nov 20, 2016 at 11:36
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    $\begingroup$ The 0.5 is an approximate value. If you charge the battery significantly beyond that number, the electrode turns into stable iron phosphate, and is thereby destroyed. There must NOT be any structural change during charging/discharging. $\endgroup$
    – Karl
    Commented Nov 20, 2016 at 11:37
  • $\begingroup$ Okay! Fair enough. But why 0.5? There should be something with this number... And can one find a formula for getting such a number, even if it is approximated (i.e. such as molar fraction etc.)? $\endgroup$
    – Physther
    Commented Nov 20, 2016 at 11:39
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    $\begingroup$ The principle of the Li-Ion battery is that you can take some fraction of the Li ions out of the cathode without structural changes, so they can also get back IN during discharging. You cannot calculate that fraction from first principles. Not with any computer from this century. $\endgroup$
    – Karl
    Commented Nov 20, 2016 at 11:47

1 Answer 1


First of all, in chemistry two types of formulas exist: structural and empirical. A structural formula shows the way atoms are connected. An empirical formula only summarizes atoms and their ratios. While often an empirical formula references a molecule, there are cases when the compound in question is not molecular, or it is unknown if it is molecular. In that case, since the total number of atoms in the molecule is undefined, the empirical formula may be scaled by any number, and as long as all indexes are scaled by the same number, it will denote exactly the same information.

So, formulations like $\ce{Ti_{0.9}O}$, and $\ce{Ti9O10}$ denote the same thing: a Ti+O phase with Ti/O ratio 0.9. Usually in such cases, if ratios are fixed, corresponding indexes are kept integral. So, it is $\ce{Al2O3}$ because the Al/O ratio is fixed here, but $\ce{Li_{0.2}MoS2}$ because the Li/Mo ratio here is not.

Returning to the $\ce{Li_xFePO4}$ issue: in this phase $\ce{FePO4}$ part forms the host network similar to quartz and thus has a fixed composition. However, Li may and does migrate in and out of the host network, so its amount in the bulk is not fixed. This is possible because Fe ions have a lot of free orbitals and some of them have rather low energy, so Li electrons are passed to iron and the small Li ions may travel through the host network. Thus the composition of the electrode changes through the charge/discharge process.

In accumulator chemistry electrodes are rarely forced towards full transfer of traveling ions, because it may lead to irreversible degradation in the electrodes. For example, the $\ce{LiCoO2}$ phase would collapse if all or even a major part of Li left, so never is all or even a major share of the Li allowed to leave it. Consequently, Li-ion battery electrodes typically contain a significant amount of Li both in the fully discharged and fully charged states.

Similarly, it's usually technically impossible to achieve complete transfer even in more traditional batteries because the voltage and consequently the travel speed of ions between electrons falls down with discharge.

  • $\begingroup$ Can one say that Li0.5 means Li/FePO4 = 0.5? Or, as Karl said in the previous comments, it is an approximate (or maybe empirical) number? $\endgroup$
    – Physther
    Commented Nov 20, 2016 at 12:07
  • $\begingroup$ @Paul One can say that by result of an analysis (or by other consideration) the apparent brutto composition of an electrode is $\ce{Li_{0.5}PO4}$ Since the compound is non-stochiometric (it allows significant change in composition without change of the phase) there is no 'ideal' composition, so any value would be a result of some form of analysis, which by definition gives approximate value (i.e. has some uncertainty) $\endgroup$
    – permeakra
    Commented Nov 20, 2016 at 12:32
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    $\begingroup$ To add here: sometimes you will even find something like "x" and "1-x" instead of the numbers, which just means that this certain substance can have those two atoms in different ratios. Or sometimes you got something like "0.1-0.5" for a certain atoms. $\endgroup$
    – DSVA
    Commented Nov 20, 2016 at 14:38
  • $\begingroup$ Thank you. Yes, I recall seeing "x" and "1-x", but I can see that only when the cathode gives away ions. But the formula of the cathode still stays "LiFePO4" (e.g. electronicsgate.com/Images/li-ion%20charger/…) Shouldn't it be LixFePO4 instead of LiFePO4? $\endgroup$
    – Physther
    Commented Nov 20, 2016 at 14:52
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    $\begingroup$ In English the counterpoint to a structural formula is typically termed the "empirical formula" (Wikipedia) - I have never encountered the term "brutto formula" before, and it doesn't seem to have an entry in the IUPAC Gold Book. $\endgroup$
    – R.M.
    Commented Nov 20, 2016 at 16:09

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