# Reduction of sugars [closed]

Why reduction of d-glucose is not generally given as compound B of the following figure? Is the formation of that compound possible? What should be its name?( since I can't find that compound I don't know it's name). Iam sure that it's not l-sorbitol.

Also I would like to know why almost all sources(on google) shows, on reduction hydroxyl group goes to right hand side (in Fischer projections)?

## closed as unclear what you're asking by Jan, Todd Minehardt, Wildcat, ringo, getafixNov 10 '16 at 12:25

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• Try to write C-6 in the starting material and C-1/C-6 in the products simply as $\ce{CH2OH}$. Are A and B still different then? – Klaus-Dieter Warzecha Nov 9 '16 at 13:42
• @KlausWarzecha No. Thanks, I got it, I was highly confused. Should I delete question? – JM97 Nov 9 '16 at 13:47

Here you have glucose reduced to sorbitol, in which the aldehyde is converted to a primary alcohol, which is an achiral carbon. Thus there will be no meaning for Fisher projection of that carbon. Thus, both the compounds $A$ and $B$ are effectively the same.