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I have to do research on a drug called Amifostine: 2-(3-aminopropylamino)ethylsulfanyl phosphonic acid.
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I'm supposed to say how the organic reaction works inside the body. I understand that it becomes hydrolysed by an enzyme become the active form; 2-((aminopropyl)amino)ethanethiol.
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I don't get what happens to the phosphonic acid functional group. Does the water break apart the S-P bond because it is a weak bond? And what does the acid group become? $\ce{H3PO4}$?

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You are expelling a thiol rather than an alcohol via alkaline phosphatase-catalyzed hydrolysis. One can also view it as a free electron pair on "X" attacking the phosphorus to pop out its =O to an anion, then the charge poking back in to expel thiolate.

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