11
$\begingroup$

I am working on synthesis homework and I can not figure out how to remove a carbon substituent from a cyclohexane.

enter image description here

What is the best way to remove the three carbons and exchange them for a ketone?

$\endgroup$
0

4 Answers 4

9
$\begingroup$

A possible pathway is as follows:

pathway

At high temperatures, formation of the more substituted alkene will be favored. Catalytic amounts of base provide a kinetic pathway for this rearrangement. $\ce{OsO4}$ creates a vicinal diol, while $\ce{NaIO4}$ cleaves the $\ce{C-C}$ bond and oxidizes the alcohols to carbonyls. Additionally, $\ce{NaIO4}$ oxidizes $\ce{(HO)2OsO2}$ back to $\ce{OsO4}$, allowing the reaction cycle to continue.

$\endgroup$
7
  • $\begingroup$ Ok thanks, I didnt know you could use base+water to rearragne a double bond like that. Very helpful $\endgroup$
    – unrnick
    Oct 22, 2016 at 17:46
  • $\begingroup$ Quick question, what program are you using to draw out the compounds? $\endgroup$
    – unrnick
    Oct 22, 2016 at 17:47
  • $\begingroup$ @unrnick ChemDraw. If you are at an uni, you should be able to get it for free $\endgroup$
    – ringo
    Oct 22, 2016 at 17:54
  • 2
    $\begingroup$ Worth noting that OsO4 is a nasty (and expensive) chemical, which leads to the main benefit of using NaIO4 as a co-oxidant: you get to use OsO4 in catalytic quantities. $\endgroup$ Oct 23, 2016 at 1:38
  • $\begingroup$ @orthocresol I wouldn’t be sure periodate is a co-catalyst here. From what I learnt, $\ce{OsO4}$ generates the diol which is periodate-cleaved to two carbonyl groups. $\endgroup$
    – Jan
    Oct 23, 2016 at 20:59
8
$\begingroup$

Here's a variation of ringo's method:

  1. Treat the alkene with $\ce{OsO4}$/$\ce{NaIO4}$ to obtain a cyclohexyl methyl ketone
  2. Convert the ketone to cyclohexyl acetate by using a peracid (MCPBA).
  3. Cleave the ester
  4. Oxidize the cyclohexanol to cyclohexanone with a mild oxidant
$\endgroup$
4
$\begingroup$

I can offer another two-step synthesis:

  1. isomerise the double bond as ringo mentioned.

  2. Criegee reaction ($\ce{O3}$) followed by workup with $\ce{PPh3}$.

$\endgroup$
1
$\begingroup$

Ozonolysis followed by reduction, elimination of water next ozonolysis (repeat till you have cyclohexanone) looks like the best solution for me.

$\endgroup$
0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.