A solution of oxalic acid is mixed with a solution of cesium hydroxide. This chemical reaction requires double displacement. I got this as my chemical equation:

$$\ce{C2H2O4 + CsOH -> H3O + CsC2O4}$$

My teacher says it is wrong, is it really incorrect?

Is the one below the right one?

$$\ce{C2H2O4 + CsOH -> CsHC2O4 + H2O}$$

  • 1
    $\begingroup$ I would start by considering what the products are. This is a special type of double displacement; it would probably also help for you to identify which one. $\endgroup$ – Zhe Oct 18 '16 at 3:21

You have a dicarboxylic acid (Oxalic Acid) reacting with a base (Cesium Hydroxide). This reaction will give you a carboxylate salt (Cesium Oxalate) and water. This is basically a neutralization reaction.

$$\ce{C2H2O4 + 2CsOH -> C2Cs2O4 + 2H2O}$$

You need 2 Cesium cations to neutralize the -2 charge of the dicarboxylic acid.

Here is an image of how Cesium oxalate looks like:

Structure of Cesium oxalate

| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.