# Finding the activation energy, when the relation between rate constant and absolute temperature is given

Here is the question I need to solve:

The rate constant is given by $\log k = 5.4 - (212/T)$
Calculate the activation energy at $127\ ^\circ\mathrm{C}$.

I know the formula

$$k = A\times e^{-{E_\mathrm{a}/RT}}$$

But, I need to know A (Arrhenius constant) to calculate the required. This value has not been provided in the question. So, what is the method to solve this sort of question?