# How to get the condensed electron configuration for Zinc ion

The question said "Write the condensed electron configuration for $\ce{Zn^{2+}}$I got [Ar] 4s$^2+$ 3d$^8$. Why was this the incorrect answer? Zinc lost 2 electrons and surely those electrons should go from the d orbitals?

By the time the $\ce{3d}$ orbitals are filled with electrons, the $\ce{4s}$ orbitals have become higher in energy, making it easier to remove them. Here are energy level curves for both the neutral and +1 forms of the $\ce{3d}$ atoms, with electron energy on the $y$-axis: