Is there any reaction for which activation energy equals total change in enthalpy for the reaction . Is it possible in the first place ? Are there any interesting examples relating this concept ?

  • $\begingroup$ That would imply zero barrier for the reverse reaction, BTW. $\endgroup$ Sep 24, 2016 at 11:48
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    $\begingroup$ What can we say about homolytic fission of... say chlorine molecule ? $\endgroup$ Sep 24, 2016 at 11:49
  • $\begingroup$ Yeah, maybe something like that. $\endgroup$ Sep 24, 2016 at 12:10
  • $\begingroup$ So we can say that activation energy for homolytic fission is same as enthalpy change for overall reaction ? It's confusing $\endgroup$ Sep 24, 2016 at 12:12
  • $\begingroup$ @getafix any help ? $\endgroup$ Sep 24, 2016 at 12:12

1 Answer 1


According to DavePhD, the following reaction satisfies the requirement:

$$\ce{O2N-NO2 -> 2NO2}$$


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