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This question already has an answer here:

Author JD Lee says in his book, Inorganic Chemistry

The dipole moment of $\ce{XeF6}$ is approximately = $0$ because the lone pair is present in the stereochemically inactive s orbital.

What is this stereochemically inactive s orbital? What does the statement mean?

PS: Please don't provide links to any web pages as I have gone crazy by the definitions they provide and also please try to explain it in an easy language and not some very technical chemistry as I am not an expert.

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marked as duplicate by Mithoron, andselisk, airhuff, paracetamol, Todd Minehardt Sep 8 '17 at 12:15

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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    $\begingroup$ Well, it means it doesn't affect stereochemistry of compound; it's shape is almost unaffected by it's presence. $\endgroup$ – Mithoron Sep 17 '16 at 20:45
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    $\begingroup$ S-orbital is spherical in shape , so any particular direction is not favoured, hence stereochemically inactive. $\endgroup$ – JM97 Sep 18 '16 at 0:12
  • $\begingroup$ Why are we closing the old question as a duplicate of the new question? (@Mithoron) $\endgroup$ – Jan Sep 8 '17 at 10:02
  • $\begingroup$ @Jan Ortho seems keen on making new better ones... $\endgroup$ – Mithoron Sep 8 '17 at 21:20
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An s-orbital is basically a pretty perfect sphere around the nucleus.

A sphere transforms upon itself no matter which element of symmetry you use. Thus, it cannot be the basis of any kind of chirality or other asymmetry.

If therefore the s-orbital is the only one that carries free electrons able to generate a dipole moment, none will be formed because it would be spherical.

(I know this answer bases quite a bit on circular — or should I say: spherical? — reasoning, but I wouldn’t know how else to write it …)

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