# Predicting product of amine elimination

From section 'Nitrogen Containing Compounds'

I spent quite a lot of time here but could not figure out the answer. It's not mentioned in my school text book either. The solution given in my book is:

I'd like to know:

1. Is the answer provided (c) correct?

2. How do I know that heating that compound in the presence of a base results in the formation of that product? We've got plenty of cases in our textbook (Tollen's Test, Fehling's Test and the aldol reaction, to name a few) where we heat organic compounds in the presence of a base, but none of them go by what happened in this question.

• Which book is it by the way? – Kartik Sep 5 '16 at 11:44

As for the mechanism, it is all there in your second picture. Indeed, that $\ce{OH-}$ would readily snatch a proton from an ammonium cation $\ce{NH4+}$, only there is no ammonium, it is a substituted ammonium, and we don't have any H linked directly to N. So we go for the next best thing and grab a proton from some carbon in $\beta$ position, simultaneously with the formation of a double bond.
The presence of larger leaving groups like $$\ce{–NR3+}$$ result in Hoffmann product than smaller leaving group like halogens. This is because the positive charge on leaving group increase the basicity of β-protons, and in the presence of bulky base like potassium tert-butoxide the Hoffmann product is the major compared to Zaitsav product. Also, if the basicity of base was increased without increasing the bulkiness of base, in that case Hoffmann product is also a major product. This is complex situation which theory tells us, but the actual situation will be known when someone conducts a particular experiment.