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Are all bond-forming processes exothermic?

If so, why don't helium form bonds with neon?

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2 Answers 2

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Yes they are, but

(1) a reaction only occurs spontaneously if it is exergonic at the given temperature, and

(2) it might not be the kind of bond you wanted. He and Ne like it much better with a van-der-Waals bond between them, and

(3) creating the spiecies that can bond can take a large amount of energy. Vaporising a solid, splitting diatomic gases, forming some unheard of He+Ne radicals, etc., and

(4) if the bond is endothermic, it simply won't form, because it is not a bound state.

Point 2-4 are basically redundand, just different ways to look at it.

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  • $\begingroup$ why don't helium form bonds with neon? $\endgroup$
    – DHMO
    Sep 4, 2016 at 10:47
  • $\begingroup$ Because any bond you could imagine, except a vdW-Bond, would be endothermic, i.e. not a bond. en.wikipedia.org/wiki/Noble_gas $\endgroup$
    – Karl
    Sep 4, 2016 at 11:49
  • $\begingroup$ So there are indeed endothermic bonds. $\endgroup$
    – DHMO
    Sep 4, 2016 at 11:54
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    $\begingroup$ Those are not bonds, because they do not bind at all! $\endgroup$
    – Karl
    Sep 4, 2016 at 11:59
  • $\begingroup$ So you're saying that if I used magic to form this molecule: $\ce{He-N}$ then the single bond would not be a bond? $\endgroup$
    – DHMO
    Sep 4, 2016 at 11:59
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i think that helium and neon are both noble gases and hence do not form bonds(because bonds are meant for those atoms who have more electrons or less electrons).yes bond forming is exothermic(courtesy https://answers.yahoo.com/question/index?qid=20090822024552AAB8qjv).

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