I was given initial concentrations for the following reaction:

$$\ce{2SO2 + O2 <=> 2SO3}\ \ \ K_c =7.5\times 10^{-2}\\ [\ce{SO3}]= 0.05\ \mathrm{M}\\ [\ce{SO2}]= 0.125\ \mathrm{M}\\ [\ce{O2}]= 0.02\ \mathrm{M}$$

What are the final concentrations?

First I calculated $Q$, and found that $Q>K_c$ so the reverse reaction is favoured.

I created an ICE table and wrote the expression for $K_c$ to solve for $x$, but the calculator says there is no solution.

Here is the ice table:

$$\begin{array}{|c|c|c|c|} \hline \ & [\ce{SO2}] & [\ce{O2}] & [\ce{SO3}]\\ \hline I & 0.125 & 0.02 & 0.05 \\ C & +2x & +x & -2x \\ E & 0.125+2x & 0.02+x & 0.05-2x\\ \hline \end{array}\\$$

$$7.5 \times 10^{-2} = \dfrac{(0.05-2x)^2}{(0.02+x)(0.125+2x)^2}$$

  • 1
    $\begingroup$ Exact duplicate of post a few down by a 'different?' user... $\endgroup$
    – Jon Custer
    Aug 27, 2016 at 12:07
  • $\begingroup$ chemistry.stackexchange.com/questions/58043/ice-tables-question Instead of simply editing you reposted it! $\endgroup$
    – Mithoron
    Aug 27, 2016 at 12:43
  • 2
    $\begingroup$ Well, does this not count as shown effort? Let's close the other one as a dupe. $\endgroup$
    – M.A.R.
    Aug 27, 2016 at 14:35

1 Answer 1


You have done everything correctly so far. Your calculator might not be able to factor the expression as it is written. It is a cubic equation with three roots and two discontinuous points. You may be used to ICE-type equilibrium problems where you can simplify parts of the expression because $x$ is small compared to the initial concentrations. This is not the case in this problem. Factoring the cubic polynomial is not always easy.

Your mass action expression can be rearranged to the following cubic equation so long as $x \ne -0.02$ and $x \ne -0.0625$, both of which are nonsense anyway. If your calculator cannot factor this expression, try using Wolfram Alpha.

$$0.3 x^3-3.9565 x^2+0.201922 x-0.00247656 = 0$$

Trying solving this equation. It has three roots, two of which are nonsense since they yield negative final concentrations. The remaining root is the answer.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.