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This question already has an answer here:

1) $$\frac{35 \; \text{cm}^2}{0.62 \; \text{cm}} = 56.4516$$

For the units in the answer, do you put $56.4516$ cm$^2$ or just $56.4516$ cm?

1) $$\frac{0.075 \; \text{g}}{0.0003 \; \text{cm}^3} = 250$$ Same here, do you put $250$ g, $250$ cm$^3,$ or $250$ g/cm$^3$?

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marked as duplicate by NotEvans., Jannis Andreska, M.A.R. ಠ_ಠ, Klaus-Dieter Warzecha, Todd Minehardt Aug 13 '16 at 17:46

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • $\begingroup$ You can do 'math' with units in the same way you do with numbers... if the units are the same then the indices can add/subtract when multipled/divided. If not, then you just string them together (or convert the units so they match) $\endgroup$ – NotEvans. Aug 13 '16 at 15:27
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    $\begingroup$ Related: May I treat units (e.g. joules, grams, etc.) in equations as variables? $\endgroup$ – Loong Aug 13 '16 at 15:59
  • $\begingroup$ as well as treating units as variables you need to consider the number of decimal places you quote in your answers relative to the number of significant digits in the numbers. $\endgroup$ – porphyrin Aug 16 '16 at 23:01
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What does $g/cm^3$ mean? It means you have divided a mass in grams by a volume in $cm^3$ (the slash character"/" is really a division). So yes, your second value is 250 $g/cm^3$.

In the first case, you can simplify $cm^2/cm$, just like in any equation, to $cm$. So your value is 56.4516 cm.

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